__Basic Exponent Rules__

- When we have the same base and we are multiplying terms, we
**add****the exponents**. $$x^2\;\times\;x^3=x^5\\xx\;\times\;xxx=xxxxx$$ - When we are dividing we
**subtract the exponents**$$\frac{x^3}{x^2}\;=x\\\frac{xxx}{xx}=x$$ - When we have an exponent raised to an exponent, we
**multiply the exponents**. (Don’t forget the coefficient is also raised to the power!) $${(x}^2)^4=x^8\\\left(xx\right)\;\times\;\left(xx\right)\;\times\;\left(xx\right)\;\times\;(xx)=xxxxxxxx\\{(2x}^2)^3={8x}^6$$ - When we have the same base and exponent, we
**add (or subtract) the coefficients**$${2x}^2+{3x}^2={5x}^2$$

** Bonus rule** for squared numbers: remember that the negatives can also be squared to get a positive number. If you have \(x^2=25\),

Those are the basic rules. **You must know them to be able to score well on the math section!**

__Advanced Exponent Rules__

There are 3 more advanced methods you may need to know for the SAT. You might need to do some combination, or all three, on the trickier problems. They are:

- With negative exponents, you simply
*flip the variable to the other side of the divisor and make the exponent positive.*$$x^{-2}=\frac1{x^2}\\\frac{x^{-2}y^3}{x^5y^{-1}}=\frac{y^1y^3}{x^5x^2}=\frac{y^4}{x^7}$$ **Changing bases**. When the answer to our crucial question,*do they have the same base?*, is*no*, see if you can rewrite one of the bases so that they are the same. You will usually have to rewrite the larger base as the smaller base to an exponent. $$2^x\;\times{\;8}^y=2^x\;\times\;(2^3)^y=2^x\;\times{\;2}^{3y}=2^{x+3y}\\\frac{3^x}{9^{-2x}}=\;3^x\;\times\;9^{2x}=3^x\;\times\;(3^2)^{2x}=\;3^x\;\times\;3^{4x}=3^{5x}$$**Switching between radicals and fractional exponents**. Radicals are fractional exponents, and fractional exponents are radicals. The most common one: $$\sqrt x=x^\frac12$$- Any time you have a fractional exponent, the number on the bottom of the fraction moves out front with the radical, and the numerator of the fraction stays with the base. $$x^\frac23=\sqrt[3]{x^2}$$
- You can convert the other way as well: $$\sqrt[4]{x^3}=x^\frac34$$
- You may see an improper fraction (numerator is larger than denominator). Remember we can split this apart. $$8^\frac43=8^\frac33\;\times\;8^\frac13=8^1\;\times\;\sqrt[3]8=8\;\times\;2=16$$

If you see an exponent problem on your test that looks totally confusing, don’t despair! You will be able to apply one or more of these rules to get to the answer.

Now back to our example problem:

Do they have the same base? \(\frac{16^{2a}}{4^{2b}}\) don’t have the same base. This means we may need to rewrite one of the bases so they are the same.

16 can be written as \(4^2\). This means our fraction could be written as: \(\frac{\left(4^2\right)^{2a}}{4^{2b}}\).

According to our exponent rules, \(\left(4^2\right)^{2a}=4^{4a}\).

Now we have \(\frac{4^{4a}}{4^{2b}}=4^{4a-2b}\).

Since \(4a-2b=3\), \(4^{4a-2b}=4^3=64\).

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